(3x+2)^2=9x^2-6x+4

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Solution for (3x+2)^2=9x^2-6x+4 equation: 



(3x+2)^2=9x^2-6x+4

We move all terms to the left:

(3x+2)^2-(9x^2-6x+4)=0

We get rid of parentheses

-9x^2+(3x+2)^2+6x-4=0

We add all the numbers together, and all the variables

-9x^2+6x+(3x+2)^2-4=0

We move all terms containing x to the left, all other terms to the right

-9x^2+6x+(3x+2)^2=4

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